观察下表:
序号
1
2
3

图形
eqIdc12aac8c2448479687a40735b3572a23    eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23    eqIdc12aac8c2448479687a40735b3572a23
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f   eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f   eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f  eqId072d7d6b911b42bc89207e72515ebf5f   eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f  eqId072d7d6b911b42bc89207e72515ebf5f   eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23
eqId072d7d6b911b42bc89207e72515ebf5f  eqId072d7d6b911b42bc89207e72515ebf5f   eqId072d7d6b911b42bc89207e72515ebf5f
eqIdc12aac8c2448479687a40735b3572a23  eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23   eqIdc12aac8c2448479687a40735b3572a23

 
我们把某格中字母和所得到的多项式称为“特征多项式”,例如第1格的“特征多项式”为eqId75f05ed289f2456ea41d208328360e1a.
回答下列问题:
(1)第3格的“特征多项式”为____________,
第4格的“特征多项式”为____________,
eqIdf458db68122849abb588feb2e682d9ac格的“特征多项式”为____________;
(2)若第1格的“特征多项式”的值为10,第2格的“特征多项式”的值为19,求eqId310ffdaaaa4b4c6d8d01aecdb7402345的值.
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