如图,对面积为s的eqId992fe44057cf4492895193f3f5398449逐次进行以下操作:
第一次操作,分别延长eqId99a3187c2b8f4bcc9703c74c3b72f1f3eqId0627be51821d4be7b3e024a354815d64eqId1eb64606273a4d63bfa90e56f9a3f5c2至点eqId346946f1395a41008d3b3b56c9ae4fbdeqIde660daa143d5431e96530c61b610d572eqIdcfc8599bedfb4ab4944abf141f348a9a,使得eqId0768bba466b0437fb8b6ff35a9c9a0f5eqIdeeaaaa999dc64f0da156150ebc5cbb2aeqId211a50e53e7d4a99978db08d311bc1e3,顺次连接eqId346946f1395a41008d3b3b56c9ae4fbdeqIde660daa143d5431e96530c61b610d572eqIdcfc8599bedfb4ab4944abf141f348a9a,得到△eqId5a0fd1dcb23d4219b1483262c39aeb03,记其面积为eqIde0b0a69153d74086acac0f2b28878dec;第二次操作,分别延长eqId31581e8b21734ef88d2a14232de7e7a6eqIdbd70ef61616a454bae30f5691884094beqIdaff253fac4314dd59cec1057787209f6至点eqId894f8d53415741dea8f7a841c68384d1eqId01ad4ec8cf0543da939adaa52264b614eqIdfe33ac7524b14f658e64c52c37499d5c,使得eqId5eb83442925c44f8885cc2737baf9987eqId3fdde5012130449ab5954577c588ecbaeqIdf530fa79464747629b2cbfe55c4283ff顺次连接eqId894f8d53415741dea8f7a841c68384d1eqId01ad4ec8cf0543da939adaa52264b614eqIdfe33ac7524b14f658e64c52c37499d5c,得到△eqId0f329d96e2a548d6a15615a8d3304ca4,记其面积为eqIdc36de5c6d722440e9911d9802c4068f8eqId3cef5f61092d4740806f69716c662b88;按此规律继续下去,可得到△eqIdc970352066d74c9c879a46352025c981,则其面积eqIde1c97d4ea27f4811a53f3dbddb5cae9e__.figure
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